The distance from the centre 6f the
dodecahedron to the centre of the pentagon is EP×1.11.The distance from the centre
of the snub cube to the centre of the pentagon
(red) is EA×1.98. These two distances are equal,
thus EA=EP×0.56
See Badoureau for application
of the pentagons (red) and truncation resulting in eighty tiangles (green)
However 60 of the 80 triangles are
scalene triangles. Thus, this snub cube is not a correct Archimedean
polyhedron.

Line 1: Application of the snub cube pentagon
(red) on
the dodecahedron pentagon acc to Badoureau
Line 2: Snub cube net and solid.
(correct Archimedean)
13b. Snub dodecahedron from
truncation of icosahedron 20/3:
The distance from the centre of the icosahedron to the centre of the triangle:
0.76 EP
The distance from the centre of the
snub cube to the centre of the triangle:
2.08 EA. Thus, EA = 0.36 EP
13c. Snub dodecahedron from truncation of truncated icosidodecahedron
30/4 20/6 12/10
The
diagonals (red) on the squares, hexagons and decagons are not of the same
length. Thus,
the edges of the snub
dodecahedron (red) are not equal and the snub dodecahedron is not a correct
Archimedean polyhedron.
