13a. Snub dodecahedron 12/5 80/3 from truncation of dodecahedron 12/5

The distance from the centre 6f the dodecahedron to the centre of the pentagon is EP×1.11.The distance from the centre

of the snub cube to the centre of the pentagon (red) is EA×1.98. These two distances are equal, thus EA=EP×0.56

See Badoureau for application of the pentagons (red) and truncation resulting in eighty tiangles (green)

However 60 of the 80 triangles are scalene triangles. Thus, this snub cube is not a correct Archimedean

polyhedron.

Line 1: Application of the snub cube pentagon (red) on

the dodecahedron pentagon acc to Badoureau

Line 2: Snub cube net and solid. (correct Archimedean)

13b. [Snub cube from truncation of icosahedron: The distance from the centre of the icosahedron to the centre of the triangle: 0.76 EP

The distance from the centre of the snub cube to the centre of the triangle: 2.08 EA. Thus, EA = 0.36 EP ]