6a.  Truncated cuboctahedron   12/4     8/6      6/8  from truncation of cube  6/4

        (Great rhombicuboctahedron)

       Data

     The distance from the centre of the cube to the center of the cube square is EP/2. The distance from the centre of the                            truncated cuboctahedron to the centre of  the octagon (red) is EA×1.91 

       These two distances are equal, thus  EA = EP× 0.26.

      Divide the EP in five parts    x + x + xÖ2 + x + x;  x= EP / (4+Ö2) =EP×0.18; EA = EP×Ö2 /(4+Ö2) = EP×0.26

  .   The distance from the octagon edge to the cube square edge is x = EP× 0.18

      Construction         

       Six octagons (red) are applied on the six cube squares.

       The eight corners (yellow) are cut off,  resulting in  eight hexagons (green-blue). The twelve edges are cut off , giving 

       twelve squares (green-blue). 

       

       . 

       (If the cuboctahedron is truncated by dividing the edges in two parts, eight triangles on the cuboctahedron triangles

          and six squares on the cuboctahedron  squares  and twelve  rectangles (edges: EP/2 and EP Ö2/2) are formed. Kepler gave

          this polyhedron the name truncated cuboctahedron , but he knew that it was not possible to perform truncation in this way.)

          

     

     Line 1: Cube, net and solid.                          A drawing for calculation of EA

                                      .                                 and for the construction

     Line 2: Truncated cuboctahedron,

                   net and solid

 

           6b. Truncated cuboctahedron from truncation of octahedron 8/3

             Data 

         The distance from the centre of the octahedron to the centre of the triangle is EP×0.41. The distance from the centre

         of the truncated cuboctahedron to the centre of the hexagon (red) is EA×2.09.

         These two distances are equal, thus  EA = EP 0.19.

        The distance between the mid-edge of the hexagon and the mid-edge of the octahedron triangle  is  in-circle radius

        of  the octagon triangle  minus in-circle  radius of the hexagon; 0.29 EP – 0.87 EA = 0.12 EP

        The distance between  the corner of the octahedron triangle and the mid-edge of the hexagon  is circus-circle radius

        of  the octahedon triangle and the in-circle radius of the hexagon ; 0.58 EP – 0.87 EA = 0.41 EP.

         Construction

        Eight hexagons (red) are applied on the  triangles of the octahedron.  The corners (yellow) and the edges (yellow) are 

      cut off resulting in twelve squares and six octagons (blue-green).(See 6a)

       

       Drawing demonstrating the site of the hexagon